SyntaxToken.WithLeadingTrivia 方法

定义

重载

WithLeadingTrivia(SyntaxTrivia[])

使用指定的前导琐事从此令牌创建新令牌。

WithLeadingTrivia(SyntaxTriviaList)

从此令牌创建一个新令牌,其中指定了前导琐事。

WithLeadingTrivia(IEnumerable<SyntaxTrivia>)

从此令牌创建一个新令牌,其中指定了前导琐事。

WithLeadingTrivia(SyntaxTrivia[])

Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs

使用指定的前导琐事从此令牌创建新令牌。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(... cli::array <Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[] trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[]? trivia);
member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTrivia[] -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (ParamArray trivia As SyntaxTrivia()) As SyntaxToken

参数

trivia
SyntaxTrivia[]

返回

适用于

WithLeadingTrivia(SyntaxTriviaList)

Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs

从此令牌创建一个新令牌,其中指定了前导琐事。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(Microsoft::CodeAnalysis::SyntaxTriviaList trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (Microsoft.CodeAnalysis.SyntaxTriviaList trivia);
member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTriviaList -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (trivia As SyntaxTriviaList) As SyntaxToken

参数

返回

适用于

WithLeadingTrivia(IEnumerable<SyntaxTrivia>)

Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs
Source:
SyntaxToken.cs

从此令牌创建一个新令牌,其中指定了前导琐事。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia> trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia>? trivia);
member this.WithLeadingTrivia : seq<Microsoft.CodeAnalysis.SyntaxTrivia> -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (trivia As IEnumerable(Of SyntaxTrivia)) As SyntaxToken

参数

返回

适用于