SyntaxNode.DescendantNodesAndTokensAndSelf 方法

定义

重载

DescendantNodesAndTokensAndSelf(Func<SyntaxNode,Boolean>, Boolean)

获取子代节点和令牌的列表, (以前缀文档顺序包括此节点) 。

DescendantNodesAndTokensAndSelf(TextSpan, Func<SyntaxNode,Boolean>, Boolean)

获取子代节点和令牌的列表, (以前缀文档顺序包括此节点) 。

DescendantNodesAndTokensAndSelf(Func<SyntaxNode,Boolean>, Boolean)

Source:
SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
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SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs

获取子代节点和令牌的列表, (以前缀文档顺序包括此节点) 。

public System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNodeOrToken> DescendantNodesAndTokensAndSelf (Func<Microsoft.CodeAnalysis.SyntaxNode,bool> descendIntoChildren = default, bool descendIntoTrivia = false);
public System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNodeOrToken> DescendantNodesAndTokensAndSelf (Func<Microsoft.CodeAnalysis.SyntaxNode,bool>? descendIntoChildren = default, bool descendIntoTrivia = false);
member this.DescendantNodesAndTokensAndSelf : Func<Microsoft.CodeAnalysis.SyntaxNode, bool> * bool -> seq<Microsoft.CodeAnalysis.SyntaxNodeOrToken>
Public Function DescendantNodesAndTokensAndSelf (Optional descendIntoChildren As Func(Of SyntaxNode, Boolean) = Nothing, Optional descendIntoTrivia As Boolean = false) As IEnumerable(Of SyntaxNodeOrToken)

参数

descendIntoChildren
Func<SyntaxNode,Boolean>

一个可选函数,用于确定搜索是否进入参数节点的子级。

descendIntoTrivia
Boolean

确定属于结构化琐事的节点是否包含在列表中。

返回

适用于

DescendantNodesAndTokensAndSelf(TextSpan, Func<SyntaxNode,Boolean>, Boolean)

Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs
Source:
SyntaxNode.cs

获取子代节点和令牌的列表, (以前缀文档顺序包括此节点) 。

public System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNodeOrToken> DescendantNodesAndTokensAndSelf (Microsoft.CodeAnalysis.Text.TextSpan span, Func<Microsoft.CodeAnalysis.SyntaxNode,bool> descendIntoChildren = default, bool descendIntoTrivia = false);
public System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNodeOrToken> DescendantNodesAndTokensAndSelf (Microsoft.CodeAnalysis.Text.TextSpan span, Func<Microsoft.CodeAnalysis.SyntaxNode,bool>? descendIntoChildren = default, bool descendIntoTrivia = false);
member this.DescendantNodesAndTokensAndSelf : Microsoft.CodeAnalysis.Text.TextSpan * Func<Microsoft.CodeAnalysis.SyntaxNode, bool> * bool -> seq<Microsoft.CodeAnalysis.SyntaxNodeOrToken>
Public Function DescendantNodesAndTokensAndSelf (span As TextSpan, Optional descendIntoChildren As Func(Of SyntaxNode, Boolean) = Nothing, Optional descendIntoTrivia As Boolean = false) As IEnumerable(Of SyntaxNodeOrToken)

参数

span
TextSpan

节点的完整跨度必须相交。

descendIntoChildren
Func<SyntaxNode,Boolean>

一个可选函数,用于确定搜索是否进入参数节点的子级。

descendIntoTrivia
Boolean

确定属于结构化琐事的节点是否包含在列表中。

返回

适用于