SyntaxGenerator.VoidReturningLambdaExpression 方法

定义

命名空间:

Microsoft.CodeAnalysis.Editing

程序集:

Microsoft.CodeAnalysis.Workspaces.dll

包:

Microsoft.CodeAnalysis.Workspaces.Common v4.9.2

重载

VoidReturningLambdaExpression(SyntaxNode)	创建一个表达式，该表达式声明返回 lambda 表达式的零参数 void。
VoidReturningLambdaExpression(IEnumerable<SyntaxNode>)	创建一个表达式，该表达式声明返回 lambda 表达式的零参数 void。
VoidReturningLambdaExpression(IEnumerable<SyntaxNode>, SyntaxNode)	创建声明 void 返回 lambda 表达式的表达式
VoidReturningLambdaExpression(IEnumerable<SyntaxNode>, IEnumerable<SyntaxNode>)	创建一个表达式，该表达式声明返回 lambda 表达式的 void。
VoidReturningLambdaExpression(String, SyntaxNode)	创建一个表达式，该表达式声明返回 lambda 表达式的单个参数 void。
VoidReturningLambdaExpression(String, IEnumerable<SyntaxNode>)	创建一个表达式，该表达式声明返回 lambda 表达式的单个参数 void。

VoidReturningLambdaExpression(SyntaxNode)

Source:

SyntaxGenerator.cs

创建一个表达式，该表达式声明返回 lambda 表达式的零参数 void。

public:
 Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(Microsoft::CodeAnalysis::SyntaxNode ^ expression);

public Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (Microsoft.CodeAnalysis.SyntaxNode expression);

member this.VoidReturningLambdaExpression : Microsoft.CodeAnalysis.SyntaxNode -> Microsoft.CodeAnalysis.SyntaxNode

Public Function VoidReturningLambdaExpression (expression As SyntaxNode) As SyntaxNode

参数

expression

SyntaxNode

返回

SyntaxNode

VoidReturningLambdaExpression(IEnumerable<SyntaxNode>)

Source:

SyntaxGenerator.cs

创建一个表达式，该表达式声明返回 lambda 表达式的零参数 void。

public:
 Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxNode ^> ^ statements);

public Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNode> statements);

member this.VoidReturningLambdaExpression : seq<Microsoft.CodeAnalysis.SyntaxNode> -> Microsoft.CodeAnalysis.SyntaxNode

Public Function VoidReturningLambdaExpression (statements As IEnumerable(Of SyntaxNode)) As SyntaxNode

参数

statements

IEnumerable<SyntaxNode>

返回

SyntaxNode

VoidReturningLambdaExpression(IEnumerable<SyntaxNode>, SyntaxNode)

Source:

SyntaxGenerator.cs

创建声明 void 返回 lambda 表达式的表达式

public:
 abstract Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxNode ^> ^ lambdaParameters, Microsoft::CodeAnalysis::SyntaxNode ^ expression);

public abstract Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNode>? lambdaParameters, Microsoft.CodeAnalysis.SyntaxNode expression);

abstract member VoidReturningLambdaExpression : seq<Microsoft.CodeAnalysis.SyntaxNode> * Microsoft.CodeAnalysis.SyntaxNode -> Microsoft.CodeAnalysis.SyntaxNode

Public MustOverride Function VoidReturningLambdaExpression (lambdaParameters As IEnumerable(Of SyntaxNode), expression As SyntaxNode) As SyntaxNode

参数

lambdaParameters

IEnumerable<SyntaxNode>

expression

SyntaxNode

返回

SyntaxNode

VoidReturningLambdaExpression(IEnumerable<SyntaxNode>, IEnumerable<SyntaxNode>)

Source:

SyntaxGenerator.cs

创建一个表达式，该表达式声明返回 lambda 表达式的 void。

public:
 abstract Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxNode ^> ^ lambdaParameters, System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxNode ^> ^ statements);

public abstract Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNode>? lambdaParameters, System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNode> statements);

abstract member VoidReturningLambdaExpression : seq<Microsoft.CodeAnalysis.SyntaxNode> * seq<Microsoft.CodeAnalysis.SyntaxNode> -> Microsoft.CodeAnalysis.SyntaxNode

Public MustOverride Function VoidReturningLambdaExpression (lambdaParameters As IEnumerable(Of SyntaxNode), statements As IEnumerable(Of SyntaxNode)) As SyntaxNode

参数

lambdaParameters

IEnumerable<SyntaxNode>

statements

IEnumerable<SyntaxNode>

返回

SyntaxNode

VoidReturningLambdaExpression(String, SyntaxNode)

Source:

SyntaxGenerator.cs

创建一个表达式，该表达式声明返回 lambda 表达式的单个参数 void。

public:
 Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(System::String ^ parameterName, Microsoft::CodeAnalysis::SyntaxNode ^ expression);

public Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (string parameterName, Microsoft.CodeAnalysis.SyntaxNode expression);

member this.VoidReturningLambdaExpression : string * Microsoft.CodeAnalysis.SyntaxNode -> Microsoft.CodeAnalysis.SyntaxNode

Public Function VoidReturningLambdaExpression (parameterName As String, expression As SyntaxNode) As SyntaxNode

参数

parameterName

String

expression

SyntaxNode

返回

SyntaxNode

VoidReturningLambdaExpression(String, IEnumerable<SyntaxNode>)

Source:

SyntaxGenerator.cs

创建一个表达式，该表达式声明返回 lambda 表达式的单个参数 void。

public:
 Microsoft::CodeAnalysis::SyntaxNode ^ VoidReturningLambdaExpression(System::String ^ parameterName, System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxNode ^> ^ statements);

public Microsoft.CodeAnalysis.SyntaxNode VoidReturningLambdaExpression (string parameterName, System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxNode> statements);

member this.VoidReturningLambdaExpression : string * seq<Microsoft.CodeAnalysis.SyntaxNode> -> Microsoft.CodeAnalysis.SyntaxNode

Public Function VoidReturningLambdaExpression (parameterName As String, statements As IEnumerable(Of SyntaxNode)) As SyntaxNode

参数

parameterName

String

statements

IEnumerable<SyntaxNode>

返回

SyntaxNode