Tokenizer<TSymbol,TSymbolType>.Stay 方法

定义

命名空间:

Microsoft.AspNetCore.Razor.Tokenizer

程序集:

Microsoft.AspNetCore.Razor.dll

包:

Microsoft.AspNetCore.Razor v1.1.0

重载

Stay(TSymbol)	返回包含指定输出的结果，并指示对 的下一次调用 Turn() 应重新调用当前状态。
Stay()	返回一个结果，指示此状态没有输出，并且计算机应保持此状态

Stay(TSymbol)

返回包含指定输出的结果，并指示对 的下一次调用 Turn() 应重新调用当前状态。

protected:
 Microsoft::AspNetCore::Razor::Tokenizer::Tokenizer<TSymbol, TSymbolType>::StateResult Stay(TSymbol result);

protected Microsoft.AspNetCore.Razor.Tokenizer.Tokenizer<TSymbol,TSymbolType>.StateResult Stay (TSymbol result);

member this.Stay : 'Symbol -> Microsoft.AspNetCore.Razor.Tokenizer.Tokenizer<'Symbol, 'SymbolType (requires 'Symbol :> Microsoft.AspNetCore.Razor.Tokenizer.Symbols.SymbolBase<'SymbolType> and 'SymbolType : struct)>.StateResult

Protected Function Stay (result As TSymbol) As Tokenizer(Of TSymbol, TSymbolType).StateResult

参数

result

TSymbol

返回

Tokenizer<TSymbol,TSymbolType>.StateResult

Stay()

返回一个结果，指示此状态没有输出，并且计算机应保持此状态

protected:
 Microsoft::AspNetCore::Razor::Tokenizer::Tokenizer<TSymbol, TSymbolType>::StateResult Stay();

protected Microsoft.AspNetCore.Razor.Tokenizer.Tokenizer<TSymbol,TSymbolType>.StateResult Stay ();

member this.Stay : unit -> Microsoft.AspNetCore.Razor.Tokenizer.Tokenizer<'Symbol, 'SymbolType (requires 'Symbol :> Microsoft.AspNetCore.Razor.Tokenizer.Symbols.SymbolBase<'SymbolType> and 'SymbolType : struct)>.StateResult

Protected Function Stay () As Tokenizer(Of TSymbol, TSymbolType).StateResult

返回

Tokenizer<TSymbol,TSymbolType>.StateResult

注解

通过不返回任何输出，状态机将再次重新调用当前状态，然后再将控制器返回到 的调用方 Turn()