STDisjoint 메서드

Determines whether the calling SqlGeometry instance is disjointed when compared against the specified SqlGeometry.

네임스페이스:  Microsoft.SqlServer.Types
어셈블리:  Microsoft.SqlServer.Types(Microsoft.SqlServer.Types.dll)

구문

‘선언
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STDisjoint ( _
    other As SqlGeometry _
) As SqlBoolean
‘사용 방법
Dim instance As SqlGeometry
Dim other As SqlGeometry
Dim returnValue As SqlBoolean

returnValue = instance.STDisjoint(other)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STDisjoint(
    SqlGeometry other
)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STDisjoint(
    SqlGeometry^ other
)

[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STDisjoint : 
        other:SqlGeometry -> SqlBoolean 

public function STDisjoint(
    other : SqlGeometry
) : SqlBoolean

매개 변수

• other
  유형: Microsoft.SqlServer.Types. . :: . .SqlGeometry
  The SqlGeometry instance to compare against the instance on which STDisjoint is invoked.

반환 값

유형: System.Data.SqlTypes. . :: . .SqlBoolean
Returns true if a SqlGeometry instance is spatially disjointed from another SqlGeometry instance. Returns false if it is not.

주의

Two SqlGeometry instances are disjointed if the intersection of their point sets is empty.

This method always returns null if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.

참고 항목

참조

SqlGeometry 클래스

Microsoft.SqlServer.Types 네임스페이스