weibull_distribution Class
The latest version of this topic can be found at weibull_distribution Class.
Generates a Weibull distribution.
Syntax
class weibull_distribution
{
public:
// types
typedef RealType result_type;
struct param_type;
// constructor and reset functions
explicit weibull_distribution(RealType a = 1.0, RealType b = 1.0);
explicit weibull_distribution(const param_type& parm);
void reset();
// generating functions
template <class URNG>
result_type operator()(URNG& gen);
template <class URNG>
result_type operator()(URNG& gen, const param_type& parm);
// property functions
RealType a() const;
RealType b() const;
param_type param() const;
void param(const param_type& parm);
result_type min() const;
result_type max() const;
};
Parameters
RealType
The floating-point result type, defaults to double. For possible types, see <random>.
Remarks
The template class describes a distribution that produces values of a user-specified integral type, or type double if none is provided, distributed according to the Weibull Distribution. The following table links to articles about individual members.
| weibull_distribution::weibull_distribution | weibull_distribution::a |
weibull_distribution::param |
weibull_distribution::operator() |
weibull_distribution::b |
weibull_distribution::param_type |
The property functions a() and b() return their respective values for stored distribution parameters a and b.
For more information about distribution classes and their members, see <random>.
For detailed information about the Weibull distribution, see the Wolfram MathWorld article Weibull Distribution.
Example
// compile with: /EHsc /W4
#include <random>
#include <iostream>
#include <iomanip>
#include <string>
#include <map>
void test(const double a, const double b, const int s) {
// uncomment to use a non-deterministic generator
// std::random_device gen;
std::mt19937 gen(1701);
std::weibull_distribution<> distr(a, b);
std::cout << std::endl;
std::cout << "min() == " << distr.min() << std::endl;
std::cout << "max() == " << distr.max() << std::endl;
std::cout << "a() == " << std::fixed << std::setw(11) << std::setprecision(10) << distr.a() << std::endl;
std::cout << "b() == " << std::fixed << std::setw(11) << std::setprecision(10) << distr.b() << std::endl;
// generate the distribution as a histogram
std::map<double, int> histogram;
for (int i = 0; i < s; ++i) {
++histogram[distr(gen)];
}
// print results
std::cout << "Distribution for " << s << " samples:" << std::endl;
int counter = 0;
for (const auto& elem : histogram) {
std::cout << std::fixed << std::setw(11) << ++counter << ": "
<< std::setw(14) << std::setprecision(10) << elem.first << std::endl;
}
std::cout << std::endl;
}
int main()
{
double a_dist = 0.0;
double b_dist = 1;
int samples = 10;
std::cout << "Use CTRL-Z to bypass data entry and run using default values." << std::endl;
std::cout << "Enter a floating point value for the 'a' distribution parameter (must be greater than zero): ";
std::cin >> a_dist;
std::cout << "Enter a floating point value for the 'b' distribution parameter (must be greater than zero): ";
std::cin >> b_dist;
std::cout << "Enter an integer value for the sample count: ";
std::cin >> samples;
test(a_dist, b_dist, samples);
}
Output
First run:
Use CTRL-Z to bypass data entry and run using default values.
Enter a floating point value for the 'a' distribution parameter (must be greater than zero): 1
Enter a floating point value for the 'b' distribution parameter (must be greater than zero): 1
Enter an integer value for the sample count: 10
min() == 0
max() == 1.79769e+308
a() == 1.0000000000
b() == 1.0000000000
Distribution for 10 samples:
1: 0.0936880533
2: 0.1225944894
3: 0.6443593183
4: 0.6551171649
5: 0.7313457551
6: 0.7313557977
7: 0.7590097389
8: 1.4466885214
9: 1.6434088411
10: 2.1201210996
Second run:
Use CTRL-Z to bypass data entry and run using default values.
Enter a floating point value for the 'a' distribution parameter (must be greater than zero): .5
Enter a floating point value for the 'b' distribution parameter (must be greater than zero): 5.5
Enter an integer value for the sample count: 10
min() == 0
max() == 1.79769e+308
a() == 0.5000000000
b() == 5.5000000000
Distribution for 10 samples:
1: 0.0482759823
2: 0.0826617486
3: 2.2835941207
4: 2.3604817485
5: 2.9417663742
6: 2.9418471657
7: 3.1685268104
8: 11.5109922290
9: 14.8543594043
10: 24.7220241239
Requirements
Header: <random>
Namespace: std
weibull_distribution::weibull_distribution
explicit weibull_distribution(RealType a = 1.0, RealType b = 1.0);
explicit weibull_distribution(const param_type& parm);
Parameters
a
The a distribution parameter.
b
The b distribution parameter.
parm
The parameter structure used to construct the distribution.
Remarks
Precondition: 0.0 < a and 0.0 < b
The first constructor constructs an object whose stored avalue holds the value a and whose stored b value holds the value b.
The second constructor constructs an object whose stored parameters are initialized from parm. You can obtain and set the current parameters of an existing distribution by calling the param() member function.
weibull_distribution::param_type
Stores the parameters of the distribution.
struct param_type {
typedef weibull_distribution<RealType> distribution_type;
param_type(RealType a = 1.0, RealType b = 1.0);
RealType a() const;
RealType b() const;
.....
bool operator==(const param_type& right) const;
bool operator!=(const param_type& right) const;
};
Parameters
See parent topic weibull_distribution Class.
Remarks
Precondition: 0.0 < a and 0.0 < b
This structure can be passed to the distribution's class constructor at instantiation, to the param() member function to set the stored parameters of an existing distribution, and to operator() to be used in place of the stored parameters.