次の方法で共有


JsonChild コンストラクター

定義

オーバーロード

JsonChild()
JsonChild(String, String, IList<JsonChild>, IList<JsonModelFeatureInformation>)

JsonChild()

ソース:
JsonChild.cs
public JsonChild ();
Public Sub New ()

適用対象

JsonChild(String, String, IList<JsonChild>, IList<JsonModelFeatureInformation>)

ソース:
JsonChild.cs
public JsonChild (string name = default, string instanceOf = default, System.Collections.Generic.IList<Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonChild> children = default, System.Collections.Generic.IList<Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonModelFeatureInformation> features = default);
new Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonChild : string * string * System.Collections.Generic.IList<Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonChild> * System.Collections.Generic.IList<Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonModelFeatureInformation> -> Microsoft.Azure.CognitiveServices.Language.LUIS.Authoring.Models.JsonChild
Public Sub New (Optional name As String = Nothing, Optional instanceOf As String = Nothing, Optional children As IList(Of JsonChild) = Nothing, Optional features As IList(Of JsonModelFeatureInformation) = Nothing)

パラメーター

name
String
instanceOf
String
children
IList<JsonChild>

適用対象