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ContextMenuService.PlacementRectangle Attached Property

  • Reference

Definition

Namespace:
System.Windows.Controls
Assembly:
PresentationFramework.dll

Gets or sets the area relative to which the context menu is positioned when it opens.

see GetPlacementRectangle, and SetPlacementRectangle
see GetPlacementRectangle, and SetPlacementRectangle
see GetPlacementRectangle, and SetPlacementRectangle

Examples

The following example assigns the same ContextMenu to two buttons and sets the HasDropShadow, Placement, PlacementRectangle, HorizontalOffset, and VerticalOffset properties to set the ContextMenu to different positions for each button.

<StackPanel>
  <StackPanel.Resources>
    <ContextMenu x:Key="myContextMenu">
      <MenuItem Header="Item"/>
    </ContextMenu>
  </StackPanel.Resources>

  <!--Both buttons use the same ContextMenu but use the
    properties on ContextMenuService to position them
    differently.-->
  <Button ContextMenu="{StaticResource myContextMenu}" 
          ContextMenuService.HasDropShadow="False" 
          ContextMenuService.Placement="Relative"
          ContextMenuService.HorizontalOffset="50"
          ContextMenuService.VerticalOffset="-10">
    button 1
  </Button>

  <Button ContextMenu="{StaticResource myContextMenu}" 
          ContextMenuService.HasDropShadow="True"
          ContextMenuService.Placement="Right"
          ContextMenuService.PlacementRectangle="0,0,30,30">
    button 2
  </Button>
</StackPanel>

Remarks

You can position a ContextMenu by setting the PlacementTarget, PlacementRectangle, Placement, HorizontalOffset, and VerticalOffsetProperty properties. These properties behave the same as they do for a Popup. For more information, see Popup Placement Behavior.

Dependency Property Information
Identifier field PlacementRectangleProperty
Metadata properties set to true None

Applies to

See also