GipGameControllerProvider.SendReceiveMessage 方法
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
傳送訊息的要求。
public:
virtual void SendReceiveMessage(GipMessageClass messageClass, byte messageId, Platform::Array <byte> ^ requestMessageBuffer, Platform::Array <byte> ^ responseMessageBuffer) = SendReceiveMessage;
void SendReceiveMessage(GipMessageClass const& messageClass, byte const& messageId, winrt::array_view <byte> const& requestMessageBuffer, winrt::array_view <byte> & responseMessageBuffer);
public void SendReceiveMessage(GipMessageClass messageClass, byte messageId, byte[] requestMessageBuffer, byte[] responseMessageBuffer);
function sendReceiveMessage(messageClass, messageId, requestMessageBuffer, responseMessageBuffer)
Public Sub SendReceiveMessage (messageClass As GipMessageClass, messageId As Byte, requestMessageBuffer As Byte(), responseMessageBuffer As Byte())
參數
- messageClass
- GipMessageClass
訊息的類別。
- messageId
-
Byte
byte
訊息的 ID。
- requestMessageBuffer
-
Byte[]
byte[]
包含要求的緩衝區。
- responseMessageBuffer
-
Byte[]
byte[]
將包含要求回應的緩衝區。