deque::operator=
Replaces the elements of this deque using the elements from another deque.
deque& operator=(
const deque& _Right
);
deque& operator=(
deque&& _Right
);
Parameters
Parameter |
Description |
_Right |
The deque that provides the new content. |
Remarks
The first override copies elements to this deque from _Right, the source of the assignment. The second override moves elements to this deque from _Right.
Elements that are contained in this deque before the operator executes are removed.
Example
// deque_operator_as.cpp
// compile with: /EHsc
#include <deque>
#include <iostream>
using namespace std;
typedef deque<int> MyDeque;
template<typename MyDeque> struct S;
template<typename MyDeque> struct S<MyDeque&> {
static void show( MyDeque& d ) {
MyDeque::const_iterator iter;
for (iter = d.cbegin(); iter != d.cend(); iter++)
cout << *iter << " ";
cout << endl;
}
};
template<typename MyDeque> struct S<MyDeque&&> {
static void show( MyDeque&& d ) {
MyDeque::const_iterator iter;
for (iter = d.cbegin(); iter != d.cend(); iter++)
cout << *iter << " ";
cout << " via unnamed rvalue reference " << endl;
}
};
int main( )
{
MyDeque d1, d2;
d1.push_back(10);
d1.push_back(20);
d1.push_back(30);
d1.push_back(40);
d1.push_back(50);
cout << "d1 = " ;
S<MyDeque&>::show( d1 );
d2 = d1;
cout << "d2 = ";
S<MyDeque&>::show( d2 );
cout << " ";
S<MyDeque&&>::show ( move< MyDeque& > (d1) );
}
Output
d1 = 10 20 30 40 50
d2 = 10 20 30 40 50
10 20 30 40 50 via unnamed rvalue reference
Requirements
Header: <deque>
Namespace: std