logical_and Struct
A predefined function object that performs the logical conjunction operation (operator&&) on its arguments.
template<class Type = void>
struct logical_and : public binary_function<Type, Type, bool>
{
bool operator()(
const Type& Left,
const Type& Right
) const;
};
// specialized transparent functor for operator&&
template<>
struct logical_and<void>
{
template<class Type1, class Type2>
auto operator()(Type1&& Left, Type2&& Right) const
-> decltype(std::forward<Type1>(Left)
&& std::forward<Type2>(Right));
};
Parameters
Type, Type1, Type2
Any type that supports an operator&& that takes operands of the specified or inferred types.Left
The left operand of the logical conjunction operation. The unspecialized template takes an lvalue reference argument of type Type. The specialized template does perfect forwarding of lvalue and rvalue reference arguments of inferred type Type1.Right
The right operand of the logical conjunction operation. The unspecialized template takes an lvalue reference argument of type Type. The specialized template does perfect forwarding of lvalue and rvalue reference arguments of inferred type Type2.
Return Value
The result of Left&&Right. The specialized template does perfect forwarding of the result, which has the type that's returned by operator&&.
Remarks
For user-defined types, there is no short-circuiting of operand evaluation. Both arguments are evaluated by operator&&.
Example
// functional_logical_and.cpp
// compile with: /EHsc
#define _CRT_RAND_S
#include <stdlib.h>
#include <deque>
#include <algorithm>
#include <functional>
#include <iostream>
int main( )
{
using namespace std;
deque<bool> d1, d2, d3( 7 );
deque<bool>::iterator iter1, iter2, iter3;
unsigned int randomValue;
int i;
for ( i = 0 ; i < 7 ; i++ )
{
if ( rand_s( &randomValue ) == 0 )
{
d1.push_back((bool)(( randomValue % 2 ) != 0));
}
}
int j;
for ( j = 0 ; j < 7 ; j++ )
{
if ( rand_s( &randomValue ) == 0 )
{
d2.push_back((bool)(( randomValue % 2 ) != 0));
}
}
cout << boolalpha; // boolalpha I/O flag on
cout << "Original deque:\n d1 = ( " ;
for ( iter1 = d1.begin( ) ; iter1 != d1.end( ) ; iter1++ )
cout << *iter1 << " ";
cout << ")" << endl;
cout << "Original deque:\n d2 = ( " ;
for ( iter2 = d2.begin( ) ; iter2 != d2.end( ) ; iter2++ )
cout << *iter2 << " ";
cout << ")" << endl;
// To find element-wise conjunction of the truth values
// of d1 & d2, use the logical_and function object
transform( d1.begin( ), d1.end( ), d2.begin( ),
d3.begin( ), logical_and<bool>( ) );
cout << "The deque which is the conjuction of d1 & d2 is:\n d3 = ( " ;
for ( iter3 = d3.begin( ) ; iter3 != d3.end( ) ; iter3++ )
cout << *iter3 << " ";
cout << ")" << endl;
}
Original deque: d1 = ( true true true true true false false ) Original deque: d2 = ( true false true true false true false ) The deque which is the conjuction of d1 & d2 is: d3 = ( true false true true false false false )
Requirements
Header: <functional>
Namespace: std