CodeGenerationUtilities.GetBaseDomainClassSchemaTypeName Method

Get the schema type name for the base class of the given domain class.

Namespace:  Microsoft.VisualStudio.Modeling.DslDefinition
Assembly:  Microsoft.VisualStudio.Modeling.Sdk.DslDefinition.10.0 (in Microsoft.VisualStudio.Modeling.Sdk.DslDefinition.10.0.dll)

Syntax

'宣告
Public Shared Function GetBaseDomainClassSchemaTypeName ( _
    domainClass As DomainClass, _
    currentNamespace As String, _
    xmlNamespaceQualifiers As Dictionary(Of DslLibrary, String) _
) As String

public static string GetBaseDomainClassSchemaTypeName(
    DomainClass domainClass,
    string currentNamespace,
    Dictionary<DslLibrary, string> xmlNamespaceQualifiers
)

public:
static String^ GetBaseDomainClassSchemaTypeName(
    DomainClass^ domainClass, 
    String^ currentNamespace, 
    Dictionary<DslLibrary^, String^>^ xmlNamespaceQualifiers
)

static member GetBaseDomainClassSchemaTypeName : 
        domainClass:DomainClass * 
        currentNamespace:string * 
        xmlNamespaceQualifiers:Dictionary<DslLibrary, string> -> string 

public static function GetBaseDomainClassSchemaTypeName(
    domainClass : DomainClass, 
    currentNamespace : String, 
    xmlNamespaceQualifiers : Dictionary<DslLibrary, String>
) : String

Parameters

• domainClass
  Type: Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass
  DomainClass whose base class schema type name will be returned.

• currentNamespace
  Type: System.String

• xmlNamespaceQualifiers
  Type: System.Collections.Generic.Dictionary<DslLibrary, String>

Return Value

Type: System.String
The schema type name of the base class of the given DomainClass or null if a base class could not be determined.

.NET Framework Security

• Full trust for the immediate caller. This member cannot be used by partially trusted code. For more information, see Using Libraries from Partially Trusted Code.

See Also

Reference

CodeGenerationUtilities Class

Microsoft.VisualStudio.Modeling.DslDefinition Namespace