string::operator+
說明如何使用 string::operator + STL Visual C++ 中的函式。
template<class _E, class _TYPE, class _A> inline
basic_string<_E, _TYPE, _A>
operator+(
const basic_string<_E, _TYPE, _A>& LString,
const _E *RCharArray
);
template<class _E, class _TYPE, class _A> inline
basic_string<_E, _TYPE, _A>
operator+(
const _E *LCharArray,
const basic_string<_E, _TYPE, _A>& RString
);
template<class _E, class _TYPE, class _A> inline
basic_string<_E, _TYPE, _A>
operator+(
const basic_string<_E, _TYPE, _A>& LString,
const _E RChar
);
template<class _E, class _TYPE, class _A> inline
basic_string<_E, _TYPE, _A>
operator+(
const _E LChar,
const basic_string<_E, _TYPE, _A>& RString
);
template<class _E, class _TYPE, class _A> inline
basic_string<_E, _TYPE, _A>
operator+(
const basic_string<_E, _TYPE, _A>& LString,
const basic_string<_E, _TYPE, _A>& RString
);
備註
注意事項 |
---|
在原型中的類別/參數名稱不相符的標頭檔中的版本。某些已修改以提高可讀性。 |
有五個版本的 string::operator + 函式。 兩個函式用來串連 null 結尾字元陣列和 basic_string。 兩個函式用來串連的字元和 basic_string。 最後一個函式用來串連兩個 basic_string 變數。
範例
// StringPlus.cpp
// compile with: /EHsc
// Illustrates how to use the operator+ to concatenate
// a null-terminated character array and a basic_string,
// how to concatenate a character and a basic_string,
// and how to concatenate two basic_string variables.
//
// Functions:
//
// operator+ : Concatenates a null-terminated character array and
// a basic_string.
// operator+ : Concatenates a character array and a basic_string.
// operator+ : Concatenates two basic_string variables.
//////////////////////////////////////////////////////////////////////
#pragma warning(disable:4786)
#include <string>
#include <iostream>
using namespace std ;
int main()
{
string result;
string S1="ABC";
string S2="DEF";
char CP1[]="GHI";
char C='J';
cout << "S1 is " << S1 << endl;
cout << "S2 is " << S2 << endl;
cout << "CP1 is " << CP1 << endl;
cout << "C is " << C << endl;
result=S1+CP1; // Function 1 (ABCGHI)
cout << "S1+CP1 is " << result << endl;
result=CP1+S1; // Function 2 (GHIABC)
cout << "CP1+S1 is " << result << endl;
result=S1+S2; // Function 3 (ABCDEF)
cout << "S1+S2 is " << result << endl;
result=S1+C; // Function 4 (ABCJ)
cout << "S1+C is " << result << endl;
result=C+S1; // Function 5 (JABC)
cout << "C+S1 is " << result << endl;
}
需求
標頭: <string>