Predicate Version of adjacent_find
說明如何使用述詞的版本的 adjacent_find Visual C++ 標準樣板程式庫 (STL) 函式。
template<class ForwardIterator, class BinaryPredicate> inline
ForwardIterator adjacent_find(
ForwardIterator First,
ForwardIterator Last,
BinaryPredicate Binary_Pred
) ;
備註
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在原型中的類別/參數名稱不相符的標頭檔中的版本。某些已修改以提高可讀性。 |
adjacent_find演算法序列中尋找連續組相符項目。 adjacent_find傳回參照範圍的第一個連續相符元件 iterator [First, Last),或最後一次,如果沒有這類的項目。 比較是使用 binary_pred 演算法的這個版本的函式。 Binary_pred 函式可以是任何使用者定義函式。 您也可以使用其中一項 STL 所提供的二進位的函式物件。
範例
// adfind2.cpp
// compile with: /EHsc
// Illustrates how to use the predicate version of
// adjacent_find function.
//
// Functions:
// adjacent_find - Locate a consecutive sequence in a range.
// disable warning C4786: symbol greater than 255 character,
// okay to ignore
#pragma warning(disable: 4786)
#include <iostream>
#include <algorithm>
#include <functional>
#include <string>
#include <vector>
using namespace std;
int main()
{
const int VECTOR_SIZE = 5 ;
// Define a template class vector of strings
typedef vector<string > StringVector ;
//Define an iterator for template class vector of strings
typedef StringVector::iterator StringVectorIt ;
StringVector NamesVect(VECTOR_SIZE) ; //vector containing names
StringVectorIt location ; // stores the position for the
// first pair of matching
// consecutive elements.
StringVectorIt start, end, it ;
// Initialize vector NamesVect
NamesVect[0] = "Aladdin" ;
NamesVect[1] = "Jasmine" ;
NamesVect[2] = "Mickey" ;
NamesVect[3] = "Minnie" ;
NamesVect[4] = "Goofy" ;
start = NamesVect.begin() ; // location of first
// element of NamesVect
end = NamesVect.end() ; // one past the location
// last element of NamesVect
// print content of NamesVect
cout << "NamesVect { " ;
for(it = start; it != end; it++)
cout << *it << ", " ;
cout << " }\n" << endl ;
// Find the first name that is lexicographically greater
// than the following name in the range [first, last + 1).
// This version performs matching using binary predicate
// function greater<string>
location = adjacent_find(start, end, greater<string>()) ;
// print the first pair of strings such that the first name is
// lexicographically greater than the second.
if (location != end)
cout << "(" << *location << ", " << *(location + 1) << ")"
<< " the first pair of strings in NamesVect such that\n"
<< "the first name is lexicographically greater than "
<< "the second\n" << endl ;
else
cout << "No consecutive pair of strings found such that\n"
<< "the first name is lexicographically greater than "
<< "the second\n" << endl ;
}
Output
NamesVect { Aladdin, Jasmine, Mickey, Minnie, Goofy, }
(Minnie, Goofy) the first pair of strings in NamesVect such that
the first name is lexicographically greater than the second
需求
標頭: <algorithm>