如何:建立集合初始設定式所使用的集合 (Visual Basic)
當您使用集合初始設定式來建立集合時,Visual Basic 編譯器會搜尋集合類型的 Add
方法,其中 Add
方法的參數符合集合初始設定式中值的類型。 這個 Add
方法可用來將集合初始設定式中的值填入集合。
範例
下列範例顯示 OrderCollection
集合,其中包含集合初始設定式可用來新增 Add
類型之物件的公用 Order
方法。 Add
方法可讓您使用縮短的集合初始設定式語法。
Public Class Customer
Public Property Id As Integer
Public Property Name As String
Public Property Orders As OrderCollection
Public Sub New(ByVal id As Integer, ByVal name As String, ByVal orders As OrderCollection)
Me.Id = id
Me.Name = name
Me.Orders = orders
End Sub
End Class
Public Class Order
Public Property Id As Integer
Public Property CustomerId As Integer
Public Property OrderDate As DateTime
Public Sub New(ByVal id As Integer,
ByVal customerId As Integer,
ByVal orderDate As DateTime)
Me.Id = id
Me.CustomerId = customerId
Me.OrderDate = orderDate
End Sub
End Class
Public Class OrderCollection
Implements IEnumerable(Of Order)
Dim items As New List(Of Order)
Public Property Item(ByVal index As Integer) As Order
Get
Return CType(Me(index), Order)
End Get
Set(ByVal value As Order)
items(index) = value
End Set
End Property
Public Sub Add(ByVal id As Integer, ByVal customerID As Integer, ByVal orderDate As DateTime)
items.Add(New Order(id, customerID, orderDate))
End Sub
Public Function GetEnumerator() As IEnumerator(Of Order) Implements IEnumerable(Of Order).GetEnumerator
Return items.GetEnumerator()
End Function
Public Function GetEnumerator1() As IEnumerator Implements IEnumerable.GetEnumerator
Return Me.GetEnumerator()
End Function
End Class
Imports System.Runtime.CompilerServices
Module Module1
<Extension()>
Sub Add(ByVal genericList As List(Of Customer),
ByVal id As Integer,
ByVal name As String,
ByVal orders As OrderCollection)
genericList.Add(New Customer(id, name, orders))
End Sub
End Module
Dim customerList = New List(Of Customer) From
{
{1, "John Rodman", New OrderCollection From {{9, 1, #6/12/2008#},
{8, 1, #6/11/2008#},
{5, 1, #5/1/2008#}}},
{2, "Ariane Berthier", New OrderCollection From {{2, 2, #1/18/2008#},
{4, 2, #3/8/2008#},
{6, 2, #3/18/2008#},
{7, 2, #5/14/2008#},
{5, 2, #4/4/2008#}}},
{3, "Brian Perry", New OrderCollection From {{1, 3, #1/15/2008#},
{3, 3, #3/8/2008#}}}
}