Point4D.Subtraction(Point4D, Point4D) 運算子
定義
重要
部分資訊涉及發行前產品,在發行之前可能會有大幅修改。 Microsoft 對此處提供的資訊,不做任何明確或隱含的瑕疵擔保。
public:
static System::Windows::Media::Media3D::Point4D operator -(System::Windows::Media::Media3D::Point4D point1, System::Windows::Media::Media3D::Point4D point2);
public static System.Windows.Media.Media3D.Point4D operator - (System.Windows.Media.Media3D.Point4D point1, System.Windows.Media.Media3D.Point4D point2);
static member ( - ) : System.Windows.Media.Media3D.Point4D * System.Windows.Media.Media3D.Point4D -> System.Windows.Media.Media3D.Point4D
Public Shared Operator - (point1 As Point4D, point2 As Point4D) As Point4D
參數
傳回
傳回 point1
與 point2
之間的差。
範例
下列範例示範如何使用多載減法運算子從 結構減去 Point4D 結構 Point4D 。
// Subtracts a Point4D from a Point4D using the overloaded - operator.
// Returns a Point4D.
Point4D point1 = new Point4D(10, 5, 1, 4);
Point4D point2 = new Point4D(15, 40, 60, 75);
Point4D pointResult = new Point4D();
pointResult = point1 - point2;
// pointResult is equal to (-5, -35, -59, -71)
// Displaying Results
syntaxString = "pointResult = point1 - point2;";
resultType = "Point4D";
operationString = "Subtracting a Vector3D from a Point4D";
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString);
' Subtracts a Point4D from a Point4D using the overloaded - operator.
' Returns a Point4D.
Dim point1 As New Point4D(10, 5, 1, 4)
Dim point2 As New Point4D(15, 40, 60, 75)
Dim pointResult As New Point4D()
pointResult = point1 - point2
' pointResult is equal to (-5, -35, -59, -71)
' Displaying Results
syntaxString = "pointResult = point1 - point2"
resultType = "Point4D"
operationString = "Subtracting a Vector3D from a Point4D"
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString)