共用方式為


RelationalStrings.IncompatibleTableCommentMismatch 方法

定義

無法對實體類型 '{entityType}' 使用資料表 '{table}',因為它正用於實體類型 '{otherEntityType}',而且批註 '{comment}' 不符合批註 '{otherComment}'。

public static string IncompatibleTableCommentMismatch (object table, object entityType, object otherEntityType, object comment, object otherComment);
public static string IncompatibleTableCommentMismatch (object? table, object? entityType, object? otherEntityType, object? comment, object? otherComment);
static member IncompatibleTableCommentMismatch : obj * obj * obj * obj * obj -> string
Public Shared Function IncompatibleTableCommentMismatch (table As Object, entityType As Object, otherEntityType As Object, comment As Object, otherComment As Object) As String

參數

table
Object
entityType
Object
otherEntityType
Object
comment
Object
otherComment
Object

傳回

適用於