SyntaxToken.WithTrailingTrivia 方法

定義

命名空間:

Microsoft.CodeAnalysis

組件:

Microsoft.CodeAnalysis.dll

套件:

Microsoft.CodeAnalysis.Common v4.9.2

多載

WithTrailingTrivia(SyntaxTrivia[])	從這個權杖建立新的權杖，並指定尾端的子系。
WithTrailingTrivia(SyntaxTriviaList)	從這個權杖建立新的權杖，並指定尾端的子系。
WithTrailingTrivia(IEnumerable<SyntaxTrivia>)	從這個權杖建立新的權杖，並指定尾端的子系。

WithTrailingTrivia(SyntaxTrivia[])

Source:

SyntaxToken.cs

從這個權杖建立新的權杖，並指定尾端的子系。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithTrailingTrivia(... cli::array <Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithTrailingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[]? trivia);

member this.WithTrailingTrivia : Microsoft.CodeAnalysis.SyntaxTrivia[] -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithTrailingTrivia (ParamArray trivia As SyntaxTrivia()) As SyntaxToken

參數

trivia

SyntaxTrivia[]

傳回

SyntaxToken

WithTrailingTrivia(SyntaxTriviaList)

Source:

SyntaxToken.cs

從這個權杖建立新的權杖，並指定尾端的子系。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithTrailingTrivia(Microsoft::CodeAnalysis::SyntaxTriviaList trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithTrailingTrivia (Microsoft.CodeAnalysis.SyntaxTriviaList trivia);

member this.WithTrailingTrivia : Microsoft.CodeAnalysis.SyntaxTriviaList -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithTrailingTrivia (trivia As SyntaxTriviaList) As SyntaxToken

參數

trivia

SyntaxTriviaList

傳回

SyntaxToken

WithTrailingTrivia(IEnumerable<SyntaxTrivia>)

Source:

SyntaxToken.cs

從這個權杖建立新的權杖，並指定尾端的子系。

public:
 Microsoft::CodeAnalysis::SyntaxToken WithTrailingTrivia(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);

public Microsoft.CodeAnalysis.SyntaxToken WithTrailingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia>? trivia);

member this.WithTrailingTrivia : seq<Microsoft.CodeAnalysis.SyntaxTrivia> -> Microsoft.CodeAnalysis.SyntaxToken

Public Function WithTrailingTrivia (trivia As IEnumerable(Of SyntaxTrivia)) As SyntaxToken

參數

trivia

IEnumerable<SyntaxTrivia>

傳回

SyntaxToken