IfDirectiveTriviaSyntax.WithIfKeyword(SyntaxToken) 方法

定義

命名空間:

Microsoft.CodeAnalysis.CSharp.Syntax

組件:

Microsoft.CodeAnalysis.CSharp.dll

套件:

Microsoft.CodeAnalysis.CSharp v4.9.2

Source:

Syntax.xml.Syntax.Generated.cs

public:
 Microsoft::CodeAnalysis::CSharp::Syntax::IfDirectiveTriviaSyntax ^ WithIfKeyword(Microsoft::CodeAnalysis::SyntaxToken ifKeyword);

public Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntax WithIfKeyword (Microsoft.CodeAnalysis.SyntaxToken ifKeyword);

member this.WithIfKeyword : Microsoft.CodeAnalysis.SyntaxToken -> Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntax

Public Function WithIfKeyword (ifKeyword As SyntaxToken) As IfDirectiveTriviaSyntax

參數

ifKeyword

SyntaxToken

傳回

IfDirectiveTriviaSyntax