Predicate Version of adjacent_find
在 Visual C++ 演示如何使用 adjacent_find 标准模板库函数的 (STL)谓词版本。
template<class ForwardIterator, class BinaryPredicate> inline
ForwardIterator adjacent_find(
ForwardIterator First,
ForwardIterator Last,
BinaryPredicate Binary_Pred
) ;
备注
备注
类/参数名在原型不匹配版本在头文件。修改某些提高可读性。
顺序 adjacent_find 算法的查找对序列中匹配的元素。 adjacent_find 返回对该范围 [First, Last) 的迭代器第一个连续的匹配元素,或之前,如果不存在这样的元素。 比较完成使用在算法的此版本的 binary_pred 功能。 binary_pred 函数可以是任何用户定义的函数。 您也可以使用 STL 提供的某二进制函数对象。
示例
// adfind2.cpp
// compile with: /EHsc
// Illustrates how to use the predicate version of
// adjacent_find function.
//
// Functions:
// adjacent_find - Locate a consecutive sequence in a range.
// disable warning C4786: symbol greater than 255 character,
// okay to ignore
#pragma warning(disable: 4786)
#include <iostream>
#include <algorithm>
#include <functional>
#include <string>
#include <vector>
using namespace std;
int main()
{
const int VECTOR_SIZE = 5 ;
// Define a template class vector of strings
typedef vector<string > StringVector ;
//Define an iterator for template class vector of strings
typedef StringVector::iterator StringVectorIt ;
StringVector NamesVect(VECTOR_SIZE) ; //vector containing names
StringVectorIt location ; // stores the position for the
// first pair of matching
// consecutive elements.
StringVectorIt start, end, it ;
// Initialize vector NamesVect
NamesVect[0] = "Aladdin" ;
NamesVect[1] = "Jasmine" ;
NamesVect[2] = "Mickey" ;
NamesVect[3] = "Minnie" ;
NamesVect[4] = "Goofy" ;
start = NamesVect.begin() ; // location of first
// element of NamesVect
end = NamesVect.end() ; // one past the location
// last element of NamesVect
// print content of NamesVect
cout << "NamesVect { " ;
for(it = start; it != end; it++)
cout << *it << ", " ;
cout << " }\n" << endl ;
// Find the first name that is lexicographically greater
// than the following name in the range [first, last + 1).
// This version performs matching using binary predicate
// function greater<string>
location = adjacent_find(start, end, greater<string>()) ;
// print the first pair of strings such that the first name is
// lexicographically greater than the second.
if (location != end)
cout << "(" << *location << ", " << *(location + 1) << ")"
<< " the first pair of strings in NamesVect such that\n"
<< "the first name is lexicographically greater than "
<< "the second\n" << endl ;
else
cout << "No consecutive pair of strings found such that\n"
<< "the first name is lexicographically greater than "
<< "the second\n" << endl ;
}
Output
NamesVect { Aladdin, Jasmine, Mickey, Minnie, Goofy, }
(Minnie, Goofy) the first pair of strings in NamesVect such that
the first name is lexicographically greater than the second
要求
**标题:**algorithm