如何:创建集合初始值设定项所使用的集合 (Visual Basic)
使用集合初始值设定项创建集合时,Visual Basic 编译器会搜索一个 Add
方法,该 Add
方法的集合类型的参数与集合初始值设定项中的值的类型相匹配。 此 Add
方法用于使用集合初始值设定项中的值来填充集合。
示例
下面的示例显示了一个 OrderCollection
集合,该集合包含一个公共 Add
方法,集合初始值设定项可使用该方法来添加 Order
类型的对象。 Add
方法使你可以使用简短的集合初始值设定项语法。
Public Class Customer
Public Property Id As Integer
Public Property Name As String
Public Property Orders As OrderCollection
Public Sub New(ByVal id As Integer, ByVal name As String, ByVal orders As OrderCollection)
Me.Id = id
Me.Name = name
Me.Orders = orders
End Sub
End Class
Public Class Order
Public Property Id As Integer
Public Property CustomerId As Integer
Public Property OrderDate As DateTime
Public Sub New(ByVal id As Integer,
ByVal customerId As Integer,
ByVal orderDate As DateTime)
Me.Id = id
Me.CustomerId = customerId
Me.OrderDate = orderDate
End Sub
End Class
Public Class OrderCollection
Implements IEnumerable(Of Order)
Dim items As New List(Of Order)
Public Property Item(ByVal index As Integer) As Order
Get
Return CType(Me(index), Order)
End Get
Set(ByVal value As Order)
items(index) = value
End Set
End Property
Public Sub Add(ByVal id As Integer, ByVal customerID As Integer, ByVal orderDate As DateTime)
items.Add(New Order(id, customerID, orderDate))
End Sub
Public Function GetEnumerator() As IEnumerator(Of Order) Implements IEnumerable(Of Order).GetEnumerator
Return items.GetEnumerator()
End Function
Public Function GetEnumerator1() As IEnumerator Implements IEnumerable.GetEnumerator
Return Me.GetEnumerator()
End Function
End Class
Imports System.Runtime.CompilerServices
Module Module1
<Extension()>
Sub Add(ByVal genericList As List(Of Customer),
ByVal id As Integer,
ByVal name As String,
ByVal orders As OrderCollection)
genericList.Add(New Customer(id, name, orders))
End Sub
End Module
Dim customerList = New List(Of Customer) From
{
{1, "John Rodman", New OrderCollection From {{9, 1, #6/12/2008#},
{8, 1, #6/11/2008#},
{5, 1, #5/1/2008#}}},
{2, "Ariane Berthier", New OrderCollection From {{2, 2, #1/18/2008#},
{4, 2, #3/8/2008#},
{6, 2, #3/18/2008#},
{7, 2, #5/14/2008#},
{5, 2, #4/4/2008#}}},
{3, "Brian Perry", New OrderCollection From {{1, 3, #1/15/2008#},
{3, 3, #3/8/2008#}}}
}