Vector64<T>.BitwiseAnd(Vector64<T>, Vector64<T>) 运算符

定义

计算两个向量的按位和两个向量。

public:
 static System::Runtime::Intrinsics::Vector64<T> operator &(System::Runtime::Intrinsics::Vector64<T> left, System::Runtime::Intrinsics::Vector64<T> right);
public static System.Runtime.Intrinsics.Vector64<T> operator & (System.Runtime.Intrinsics.Vector64<T> left, System.Runtime.Intrinsics.Vector64<T> right);
static member ( &&& ) : System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> * System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)> -> System.Runtime.Intrinsics.Vector64<'T (requires 'T : struct)>
Public Shared Operator And (left As Vector64(Of T), right As Vector64(Of T)) As Vector64(Of T)

参数

left
Vector64<T>

要按位和具有 right的向量。

right
Vector64<T>

要按位和具有 left的向量。

返回

Vector64<T>

按位和 leftright

适用于