SyntaxToken.WithLeadingTrivia 方法
定义
重要
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重载
WithLeadingTrivia(SyntaxTrivia[]) |
使用指定的前导琐事从此令牌创建新令牌。 |
WithLeadingTrivia(SyntaxTriviaList) |
从此令牌创建一个新令牌,其中指定了前导琐事。 |
WithLeadingTrivia(IEnumerable<SyntaxTrivia>) |
从此令牌创建一个新令牌,其中指定了前导琐事。 |
WithLeadingTrivia(SyntaxTrivia[])
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
使用指定的前导琐事从此令牌创建新令牌。
public:
Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(... cli::array <Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[] trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (params Microsoft.CodeAnalysis.SyntaxTrivia[]? trivia);
member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTrivia[] -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (ParamArray trivia As SyntaxTrivia()) As SyntaxToken
参数
- trivia
- SyntaxTrivia[]
返回
适用于
WithLeadingTrivia(SyntaxTriviaList)
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
从此令牌创建一个新令牌,其中指定了前导琐事。
public:
Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(Microsoft::CodeAnalysis::SyntaxTriviaList trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (Microsoft.CodeAnalysis.SyntaxTriviaList trivia);
member this.WithLeadingTrivia : Microsoft.CodeAnalysis.SyntaxTriviaList -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (trivia As SyntaxTriviaList) As SyntaxToken
参数
- trivia
- SyntaxTriviaList
返回
适用于
WithLeadingTrivia(IEnumerable<SyntaxTrivia>)
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
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- SyntaxToken.cs
从此令牌创建一个新令牌,其中指定了前导琐事。
public:
Microsoft::CodeAnalysis::SyntaxToken WithLeadingTrivia(System::Collections::Generic::IEnumerable<Microsoft::CodeAnalysis::SyntaxTrivia> ^ trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia> trivia);
public Microsoft.CodeAnalysis.SyntaxToken WithLeadingTrivia (System.Collections.Generic.IEnumerable<Microsoft.CodeAnalysis.SyntaxTrivia>? trivia);
member this.WithLeadingTrivia : seq<Microsoft.CodeAnalysis.SyntaxTrivia> -> Microsoft.CodeAnalysis.SyntaxToken
Public Function WithLeadingTrivia (trivia As IEnumerable(Of SyntaxTrivia)) As SyntaxToken
参数
- trivia
- IEnumerable<SyntaxTrivia>