IToIntBiFunction.ApplyAsInt(Object, Object) 方法

参考

定义

命名空间:: Java.Util.Functions

程序集:: Mono.Android.dll

重要

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将此函数应用于给定参数。

[Android.Runtime.Register("applyAsInt", "(Ljava/lang/Object;Ljava/lang/Object;)I", "GetApplyAsInt_Ljava_lang_Object_Ljava_lang_Object_Handler:Java.Util.Functions.IToIntBiFunctionInvoker, Mono.Android, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null", ApiSince=24)]
public int ApplyAsInt (Java.Lang.Object? t, Java.Lang.Object? u);

[<Android.Runtime.Register("applyAsInt", "(Ljava/lang/Object;Ljava/lang/Object;)I", "GetApplyAsInt_Ljava_lang_Object_Ljava_lang_Object_Handler:Java.Util.Functions.IToIntBiFunctionInvoker, Mono.Android, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null", ApiSince=24)>]
abstract member ApplyAsInt : Java.Lang.Object * Java.Lang.Object -> int