How to: Define a Conversion Operator (Visual Basic)

Artikel
02/04/2013

If you have defined a class or structure, you can define a type conversion operator between the type of your class or structure and another data type (such as Integer, Double, or String).

Define the type conversion as a CType Function (Visual Basic) procedure within the class or structure. All conversion procedures must be Public Shared, and each one must specify either Widening (Visual Basic) or Narrowing (Visual Basic).

Defining an operator on a class or structure is also called overloading the operator.

Example

The following example defines conversion operators between a structure called digit and a Byte.

Public Structure digit
Private dig As Byte
    Public Sub New(ByVal b As Byte)
        If (b < 0 OrElse b > 9) Then Throw New System.ArgumentException(
            "Argument outside range for Byte")
        Me.dig = b
    End Sub
    Public Shared Widening Operator CType(ByVal d As digit) As Byte
        Return d.dig
    End Operator
    Public Shared Narrowing Operator CType(ByVal b As Byte) As digit
        Return New digit(b)
    End Operator
End Structure

You can test the structure digit with the following code.

Public Sub consumeDigit()
    Dim d1 As New digit(4)
    Dim d2 As New digit(7)
    Dim d3 As digit = CType(CByte(3), digit)
    Dim s As String = "Initial 4 generates " & CStr(CType(d1, Byte)) &
          vbCrLf & "Initial 7 generates " & CStr(CType(d2, Byte)) &
          vbCrLf & "Converted 3 generates " & CStr(CType(d3, Byte))
    Try
        Dim d4 As digit
        d4 = CType(CType(d1, Byte) + CType(d2, Byte), digit)
    Catch e4 As System.Exception
        s &= vbCrLf & "4 + 7 generates " & """" & e4.Message & """"
    End Try
    Try
        Dim d5 As digit = CType(CByte(10), digit)
    Catch e5 As System.Exception
        s &= vbCrLf & "Initial 10 generates " & """" & e5.Message & """"
    End Try
    MsgBox(s)
End Sub

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How to: Define a Conversion Operator (Visual Basic)

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