const_pointer_cast
Const cast to shared_ptr.
template <class Ty, class Other>
shared_ptr<Ty> const_pointer_cast(const shared_ptr<Other>& sp);
Parameters
Ty
The type controlled by the returned shared pointer.Other
The type controlled by the argument shared pointer.Other
The argument shared pointer.
Remarks
The template function returns an empty shared_ptr object if const_cast<Ty*>(sp.get()) returns a null pointer; otherwise it returns a shared_ptr Class<Ty> object that owns the resource that is owned by sp. The expression const_cast<Ty*>(sp.get()) must be valid.
Example
// std_tr1__memory__const_pointer_cast.cpp
// compile with: /EHsc
#include <memory>
#include <iostream>
int main()
{
std::shared_ptr<int> sp0(new int);
std::shared_ptr<const int> sp1 =
std::const_pointer_cast<const int>(sp0);
*sp0 = 3;
std::cout << "sp1 == " << *sp1 << std::endl;
return (0);
}
sp1 == 3
Requirements
Header: <memory>
Namespace: std