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Свойство CurrentRunStatus

Gets the current execution status of the job.

Пространство имен:  Microsoft.SqlServer.Management.Smo.Agent
Сборка:  Microsoft.SqlServer.Smo (в Microsoft.SqlServer.Smo.dll)

Синтаксис

'Декларация
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.Expensive Or SfcPropertyFlags.Standalone)> _
Public ReadOnly Property CurrentRunStatus As JobExecutionStatus
    Get
'Применение
Dim instance As Job
Dim value As JobExecutionStatus

value = instance.CurrentRunStatus

[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)]
public JobExecutionStatus CurrentRunStatus { get; }

[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::Expensive|SfcPropertyFlags::Standalone)]
public:
property JobExecutionStatus CurrentRunStatus {
    JobExecutionStatus get ();
}

[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)>]
member CurrentRunStatus : JobExecutionStatus

function get CurrentRunStatus () : JobExecutionStatus

Значение свойства

Тип: Microsoft.SqlServer.Management.Smo.Agent. . :: . .JobExecutionStatus
A JobExecutionStatus object value that specifies the current execution status of the job.

Примеры

The following code example creates a new job and displays its status.

C#

Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
Console.WriteLine(jb.CurrentRunStatus);

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Test Job")
$jb.Create()
Write-Host $jb.CurrentRunStatus