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Метод SendXmlaRequest (XmlaRequestType, Stream)

Sends an XML for Analysis (XMLA) request of the specified type using the specified stream.

Пространство имен:  Microsoft.AnalysisServices
Сборка:  Microsoft.AnalysisServices (в Microsoft.AnalysisServices.dll)

Синтаксис

'Декларация
Public Function SendXmlaRequest ( _
    type As XmlaRequestType, _
    requestStream As Stream _
) As XmlReader
'Применение
Dim instance As Server
Dim type As XmlaRequestType
Dim requestStream As Stream
Dim returnValue As XmlReader

returnValue = instance.SendXmlaRequest(type, _
    requestStream)

public XmlReader SendXmlaRequest(
    XmlaRequestType type,
    Stream requestStream
)

public:
XmlReader^ SendXmlaRequest(
    XmlaRequestType type, 
    Stream^ requestStream
)

member SendXmlaRequest : 
        type:XmlaRequestType * 
        requestStream:Stream -> XmlReader 

public function SendXmlaRequest(
    type : XmlaRequestType, 
    requestStream : Stream
) : XmlReader

Параметры

Возвращаемое значение

Тип: System.Xml. . :: . .XmlReader
An XmlReader containing the results of the request.