LambdaExpressionSyntax.WithBlock(BlockSyntax) Method
Definition
Important
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public Microsoft.CodeAnalysis.CSharp.Syntax.LambdaExpressionSyntax WithBlock (Microsoft.CodeAnalysis.CSharp.Syntax.BlockSyntax? block);override this.WithBlock : Microsoft.CodeAnalysis.CSharp.Syntax.BlockSyntax -> Microsoft.CodeAnalysis.CSharp.Syntax.LambdaExpressionSyntaxPublic Function WithBlock (block As BlockSyntax) As LambdaExpressionSyntaxParameters
- block
- BlockSyntax
Returns
Applies to
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