Artigo
11/18/2011

Enumerable.Min Method (IEnumerable<Nullable<Double>>)

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Returns the minimum value in a sequence of nullable Double values.

Namespace: System.Linq
Assembly: System.Core (in System.Core.dll)

Syntax

'Declaration
<ExtensionAttribute> _
Public Shared Function Min ( _
    source As IEnumerable(Of Nullable(Of Double)) _
) As Nullable(Of Double)

public static Nullable<double> Min(
    this IEnumerable<Nullable<double>> source
)

Parameters

source
Type: System.Collections.Generic.IEnumerable<Nullable<Double>>
A sequence of nullable Double values to determine the minimum value of.

Return Value

Type: System.Nullable<Double>
A value of type Nullable<Double> in C# or Nullable(Of Double) in Visual Basic that corresponds to the minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Nullable<Double>>. When you use instance method syntax to call this method, omit the first parameter.

Exceptions

Exception	Condition
ArgumentNullException	source is nulla null reference (Nothing in Visual Basic).

Remarks

The Min(IEnumerable<Nullable<Double>>) method uses the Double implementation of IComparable<T> to compare values.

If the source sequence is empty or contains only values that are nulla null reference (Nothing in Visual Basic), this function returns nulla null reference (Nothing in Visual Basic).

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

Examples

The following code example demonstrates how to use Min(IEnumerable<Nullable<Int32>>) to determine the minimum value in a sequence.

Note:
This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

      Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
      Dim min As Nullable(Of Integer) = grades.Min()

      ' Display the output.
      outputBlock.Text &= "The lowest grade is " & min & vbCrLf

      ' This code produces the following output:
      '
      ' The lowest grade is 37

      int?[] grades = { 78, 92, null, 99, 37, 81 };

      int? min = grades.Min();

      outputBlock.Text += String.Format("The lowest grade is {0}.", min) + "\n";

      /*
       This code produces the following output:

       The lowest grade is 37.
      */

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

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