reverse_iterator::operator

Returns a reference to an element offset from the element addressed by a reverse_iterator by a specified number of positions.

reference operator[]( 
   difference_type _Off 
) const;

Parameters

• _Off
  The offset from the reverse_iterator address.

Return Value

The reference to the element offset.

Remarks

The operator returns *(*this + _Off).

Example

// reverse_iterator_ret_ref.cpp
// compile with: /EHsc
#include <iterator>
#include <algorithm>
#include <vector>
#include <iostream>

int main( )
{
   using namespace std;
   int i;

   vector<int> vec;
   for (i = 1 ; i < 6 ; ++i )
   {
      vec.push_back ( 2 * i );
   }
   
   vector <int>::iterator vIter;
   cout << "The vector vec is: ( ";
   for ( vIter = vec.begin ( ) ; vIter != vec.end ( ); vIter++ )
      cout << *vIter << " ";
   cout << ")." << endl;

   vector <int>::reverse_iterator rvIter;
   cout << "The vector vec reversed is: ( ";
   for ( rvIter = vec.rbegin( ) ; rvIter != vec.rend( ); rvIter++)
      cout << *rvIter << " ";
   cout << ")." << endl;

   vector <int>::iterator pos;
   pos = find ( vec.begin ( ), vec.end ( ), 8 );
   reverse_iterator<vector<int>::iterator> rpos ( pos );

   // Declare a difference type for a parameter
   reverse_iterator<vector<int>::iterator>::difference_type diff = 2;

   cout << "The iterator pos points to: " << *pos << "." << endl;
   cout << "The iterator rpos points to: " << *rpos << "." << endl;

   // Declare a reference return type & use operator[]
   reverse_iterator<vector<int>::iterator>::reference refrpos = rpos [diff];
   cout << "The iterator rpos now points to: " << refrpos << "." << endl;   
}

The vector vec is: ( 2 4 6 8 10 ).
The vector vec reversed is: ( 10 8 6 4 2 ).
The iterator pos points to: 8.
The iterator rpos points to: 6.
The iterator rpos now points to: 2.

Requirements

Header: <iterator>

Namespace: std

See Also

Reference

reverse_iterator Class

Standard Template Library