iscntrl

Testa se um elemento em uma localidade é um caractere de controle.

template<Class CharType>
   bool iscntrl(
      CharType _Ch, 
      const locale& _Loc
   )

Parâmetros

• _Ch
  o elemento a ser testado.

• _Loc
  A localidade que contém o elemento a ser testado.

Valor de retorno

true se o elemento testado é um caractere de controle; false se não é.

Comentários

A função do modelo retorna use_facet<ctype<CharType> >(_Loc).é(ctype<CharType>::cntrl, _Ch).

Exemplo

// locale_iscntrl.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )   
{
   locale loc ( "German_Germany" );
   bool result1 = iscntrl ( 'L', loc );
   bool result2 = iscntrl ( '\n', loc );
   bool result3 = iscntrl ( '\t', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is "
           << "a control character." << endl;
   else
      cout << "The character 'L' in the locale is "
           << " not a control character." << endl;

   if ( result2 )
      cout << "The character-set 'backslash-n' in the locale\n is "
           << "a control character." << endl;
   else
      cout << "The character-set 'backslash-n' in the locale\n is "
           << " not a control character." << endl;

   if ( result3 )
      cout << "The character-set 'backslash-t' in the locale\n is "
           << "a control character." << endl;
   else
      cout << "The character-set 'backslash-n' in the locale \n is "
           << " not a control character." << endl;
}

Saída

The character 'L' in the locale is  not a control character.
The character-set 'backslash-n' in the locale
 is a control character.
The character-set 'backslash-t' in the locale
 is a control character.

Requisitos

Cabeçalho: <locale>

namespace: STD