isgraph
Tests whether an element in a locale is an alphanumeric or punctuation character.
template<Class CharType>
bool isgraph(
CharType _Ch,
const locale& _Loc
)
Parameters
_Ch
The element to be tested._Loc
The locale containing the element to be tested.
Return Value
true if the element tested is an alphanumeric or a punctuation character; false if it is not.
Remarks
The template function returns use_facet<ctype<CharType> >(_Loc).is(ctype<CharType>::graph, _Ch).
Example
// locale_is_graph.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>
using namespace std;
int main( )
{
locale loc ( "German_Germany" );
bool result1 = isgraph ( 'L', loc );
bool result2 = isgraph ( '\t', loc );
bool result3 = isgraph ( '.', loc );
if ( result1 )
cout << "The character 'L' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character 'L' in the locale is\n "
<< " not an alphanumeric or punctuation character." << endl;
if ( result2 )
cout << "The character 'backslash-t' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character 'backslash-t' in the locale is\n "
<< "not an alphanumeric or punctuation character." << endl;
if ( result3 )
cout << "The character '.' in the locale is\n "
<< "an alphanumeric or punctuation character." << endl;
else
cout << "The character '.' in the locale is\n "
<< " not an alphanumeric or punctuation character." << endl;
}
Output
The character 'L' in the locale is
an alphanumeric or punctuation character.
The character 'backslash-t' in the locale is
not an alphanumeric or punctuation character.
The character '.' in the locale is
an alphanumeric or punctuation character.
Requirements
Header: <locale>
Namespace: std