list::operator=
Replaces the elements of the list with a copy of another list.
list& operator=(
const list& _Right
);
list& operator=(
list&& _Right
);
Parameters
Parameter |
Description |
_Right |
The list Class being copied into the list. |
Remarks
After erasing any existing elements in a list, the operator either copies or moves the contents of _Right into the list.
Example
// list_operator_as.cpp
// compile with: /EHsc
#include <list>
#include <iostream>
int main( )
{
using namespace std;
list<int> v1, v2, v3;
list<int>::iterator iter;
v1.push_back(10);
v1.push_back(20);
v1.push_back(30);
v1.push_back(40);
v1.push_back(50);
cout << "v1 = " ;
for (iter = v1.begin(); iter != v1.end(); iter++)
cout << *iter << " ";
cout << endl;
v2 = v1;
cout << "v2 = ";
for (iter = v2.begin(); iter != v2.end(); iter++)
cout << *iter << " ";
cout << endl;
// move v1 into v2
v2.clear();
v2 = forward< list<int> >(v1);
cout << "v2 = ";
for (iter = v2.begin(); iter != v2.end(); iter++)
cout << *iter << " ";
cout << endl;
}
Output
v1 = 10 20 30 40 50
v2 = 10 20 30 40 50
v2 = 10 20 30 40 50
Requirements
Header: <list>
Namespace: std