locale::operator!=
Tests two locales for inequality.
bool operator!=(
const locale& _Right
) const;
Parameters
- _Right
One of the locales to be tested for inequality.
Return Value
A Boolean value that is true if the locales are not copies of the same locale; false if the locales are copies of the same locale.
Remarks
Two locales are equal if they are the same locale, if one is a copy of the other, or if they have identical names.
Example
// locale_op_ne.cpp
// compile with: /EHsc
#include <iostream>
#include <string>
#include <locale>
using namespace std;
int main( )
{
locale loc1( "German_Germany" );
locale loc2( "German_Germany" );
locale loc3( "English" );
if ( loc1 != loc2 )
cout << "locales loc1 (" << loc1.name( )
<< ") and\n loc2 (" << loc2.name( ) << ") are not equal." << endl;
else
cout << "locales loc1 (" << loc1.name( )
<< ") and\n loc2 (" << loc2.name( ) << ") are equal." << endl;
if ( loc1 != loc3 )
cout << "locales loc1 (" << loc1.name( )
<< ") and\n loc3 (" << loc3.name( ) << ") are not equal." << endl;
else
cout << "locales loc1 (" << loc1.name( )
<< ") and\n loc3 (" << loc3.name( ) << ") are equal." << endl;
}
locales loc1 (German_Germany.1252) and loc2 (German_Germany.1252) are equal. locales loc1 (German_Germany.1252) and loc3 (English_United States.1252) are not equal.
Requirements
Header: <locale>
Namespace: std