Convert.ToUInt32 Method (String, Int32)
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Converts the string representation of a number in a specified base to an equivalent 32-bit unsigned integer.
This API is not CLS-compliant.
Namespace: System
Assembly: mscorlib (in mscorlib.dll)
Syntax
'Declaration
<CLSCompliantAttribute(False)> _
Public Shared Function ToUInt32 ( _
value As String, _
fromBase As Integer _
) As UInteger
[CLSCompliantAttribute(false)]
public static uint ToUInt32(
string value,
int fromBase
)
Parameters
- value
Type: System.String
A string containing a number.
- fromBase
Type: System.Int32
The base of the number in value, which must be 2, 8, 10, or 16.
Return Value
Type: System.UInt32
A 32-bit unsigned integer equivalent to the number in value.
-or-
Zero if value is nulla null reference (Nothing in Visual Basic).
Exceptions
| Exception | Condition |
|---|---|
| ArgumentException | fromBase is not 2, 8, 10, or 16. -or- value, which represents a non-base 10 unsigned number, is prefixed with a negative sign. |
| FormatException | value contains a character that is not a valid digit in the base specified by fromBase. The exception message indicates that there are no digits to convert if the first character in value is invalid; otherwise, the message indicates that value contains invalid trailing characters. |
| OverflowException | value, which represents a non-base 10 unsigned number, is prefixed with a negative sign. -or- The return value is less than UInt32.MinValue or larger than UInt32.MaxValue. |
Remarks
If fromBase is 16, you can prefix the number specified by the value parameter with "0x" or "0X".
Because the UInt32 data type supports unsigned values only, the ToUInt32(String, Int32) method assumes that value is expressed using unsigned binary representation. In other words, all 32 bits are used to represent the numeric value and a sign bit is absent. As a result, it is possible to write code in which a signed integer value that is out of the range of the UInt32 data type is converted to a UInt32 value without the method throwing an exception. The following example converts MinValue to its hexadecimal string representation and then calls the ToUInt32(String, Int32) method. Rather than throwing an exception, the method displays the message, "0x80000000 converts to 2147483648."
' Create a hexadecimal value out of range of the UInt32 type.
Dim value As String = Convert.ToString(Integer.MinValue, 16)
' Convert it back to a number.
Try
Dim number As UInt32 = Convert.ToUInt32(value, 16)
outputBlock.Text += String.Format("0x{0} converts to {1}.", value, number) & vbCrLf
Catch e As OverflowException
outputBlock.Text += String.Format("Unable to convert '0x{0}' to an unsigned integer.", _
value) & vbCrLf
End Try
// Create a hexadecimal value out of range of the UInt32 type.
string value = Convert.ToString(Int32.MinValue, 16);
// Convert it back to a number.
try
{
UInt32 number = Convert.ToUInt32(value, 16);
outputBlock.Text += String.Format("0x{0} converts to {1}.", value, number) + "\n";
}
catch (OverflowException)
{
outputBlock.Text += String.Format("Unable to convert '0x{0}' to an unsigned integer.",
value) + "\n";
}
When performing binary operations or numeric conversions, it is always the responsibility of the developer to verify that a method or operator uses the appropriate numeric representation to interpret a particular value. The following example illustrates one technique for ensuring that the method does not inappropriately use binary representation to interpret a value that uses two's complement representation when converting a hexadecimal string to a UInt32 value. It determines whether a value represents a signed or an unsigned integer at the same time that it converts that value to its string representation. When converting the value to a UInt32 value, the example checks whether the original value was a signed integer. If so, and its high-order bit is set (which indicates that the original value was negative), the method throws an exception.
' Create a negative hexadecimal value out of range of the UInt32 type.
Dim sourceNumber As Integer = Integer.MinValue
Dim isSigned As Boolean = Math.Sign(Integer.MinValue) = -1
Dim value As String = Convert.ToString(sourceNumber, 16)
Dim targetNumber As UInt32
Try
targetNumber = Convert.ToUInt32(value, 16)
If isSigned And ((targetNumber And &H80000000) <> 0) Then
Throw New OverflowException()
Else
outputBlock.Text += String.Format("0x{0} converts to {1}.", value, targetNumber) & vbCrLf
End If
Catch e As OverflowException
outputBlock.Text += String.Format("Unable to convert '0x{0}' to an unsigned integer.", _
value) & vbCrLf
End Try
' Displays the following:
' Unable to convert '0x80000000' to an unsigned integer.
// Create a negative hexadecimal value out of range of the UInt32 type.
int sourceNumber = Int32.MinValue;
bool isSigned = Math.Sign((int)sourceNumber.GetType().GetField("MinValue").GetValue(null)) == -1;
string value = Convert.ToString(sourceNumber, 16);
UInt32 targetNumber;
try
{
targetNumber = Convert.ToUInt32(value, 16);
if (isSigned && ((targetNumber & 0x80000000) != 0))
throw new OverflowException();
else
outputBlock.Text += String.Format("0x{0} converts to {1}.", value, targetNumber) + "\n";
}
catch (OverflowException)
{
outputBlock.Text += String.Format("Unable to convert '0x{0}' to an unsigned integer.",
value) + "\n";
}
// Displays the following:
// Unable to convert '0x80000000' to an unsigned integer.
Version Information
Silverlight
Supported in: 5, 4, 3
Silverlight for Windows Phone
Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0
XNA Framework
Supported in: Xbox 360, Windows Phone OS 7.0
Platforms
For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.