iscntrl
Sprawdza, czy element w ustawieniach regionalnych jest znak kontrolny.
template<Class CharType>
bool iscntrl(
CharType _Ch,
const locale& _Loc
)
Parametry
_Ch
Element ma być testowane._Loc
Ustawienia regionalne, zawierający element ma być badana.
Wartość zwracana
TRUE Jeśli element testowane jest znak kontrolny; false Jeśli nie jest.
Uwagi
Funkcja szablonu zwraca use_facet<ctype<CharType>>(_Loc).is(ctype<CharType>::cntrl, _Ch).
Przykład
// locale_iscntrl.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>
using namespace std;
int main( )
{
locale loc ( "German_Germany" );
bool result1 = iscntrl ( 'L', loc );
bool result2 = iscntrl ( '\n', loc );
bool result3 = iscntrl ( '\t', loc );
if ( result1 )
cout << "The character 'L' in the locale is "
<< "a control character." << endl;
else
cout << "The character 'L' in the locale is "
<< " not a control character." << endl;
if ( result2 )
cout << "The character-set 'backslash-n' in the locale\n is "
<< "a control character." << endl;
else
cout << "The character-set 'backslash-n' in the locale\n is "
<< " not a control character." << endl;
if ( result3 )
cout << "The character-set 'backslash-t' in the locale\n is "
<< "a control character." << endl;
else
cout << "The character-set 'backslash-n' in the locale \n is "
<< " not a control character." << endl;
}
Dane wyjściowe
The character 'L' in the locale is not a control character.
The character-set 'backslash-n' in the locale
is a control character.
The character-set 'backslash-t' in the locale
is a control character.
Wymagania
Nagłówek:<ustawień regionalnych>
Przestrzeń nazw: std