How to: Rotate, Reflect, and Skew Images
You can rotate, reflect, and skew an image by specifying destination points for the upper-left, upper-right, and lower-left corners of the original image. The three destination points determine an affine transformation that maps the original rectangular image to a parallelogram.
Example
For example, suppose the original image is a rectangle with upper-left corner at (0, 0), upper-right corner at (100, 0), and lower-left corner at (0, 50). Now suppose you map those three points to destination points as follows.
Original point |
Destination point |
---|---|
Upper-left (0, 0) |
(200, 20) |
Upper-right (100, 0) |
(110, 100) |
Lower-left (0, 50) |
(250, 30) |
The following illustration shows the original image and the image mapped to the parallelogram. The original image has been skewed, reflected, rotated, and translated. The x-axis along the top edge of the original image is mapped to the line that runs through (200, 20) and (110, 100). The y-axis along the left edge of the original image is mapped to the line that runs through (200, 20) and (250, 30).
The following illustration shows a similar transformation applied to a photographic image.
The following illustration shows a similar transformation applied to a metafile.
The following example produces the images shown in the first illustration.
' New Point(200, 20) = destination for upper-left point of original
' New Point(110, 100) = destination for upper-right point of original
' New Point(250, 30) = destination for lower-left point of original
Dim destinationPoints As Point() = { _
New Point(200, 20), _
New Point(110, 100), _
New Point(250, 30)}
Dim image As New Bitmap("Stripes.bmp")
' Draw the image unaltered with its upper-left corner at (0, 0).
e.Graphics.DrawImage(image, 0, 0)
' Draw the image mapped to the parallelogram.
e.Graphics.DrawImage(image, destinationPoints)
Point[] destinationPoints = {
new Point(200, 20), // destination for upper-left point of
// original
new Point(110, 100), // destination for upper-right point of
// original
new Point(250, 30)}; // destination for lower-left point of
// original
Image image = new Bitmap("Stripes.bmp");
// Draw the image unaltered with its upper-left corner at (0, 0).
e.Graphics.DrawImage(image, 0, 0);
// Draw the image mapped to the parallelogram.
e.Graphics.DrawImage(image, destinationPoints);
Compiling the Code
The preceding example is designed for use with Windows Forms, and it requires PaintEventArgs e, which is a parameter of the Paint event handler. Make sure to replace Stripes.bmp with the path to an image that is valid on your system.