IVsUIShell2.GetOpenFileNameViaDlgEx(VSOPENFILENAMEW[], String) Method

Definition

Namespace:

Microsoft.VisualStudio.Shell.Interop

Assembly:

Microsoft.VisualStudio.Interop.dll

Package:

Microsoft.VisualStudio.Interop v17.12.40391

Brings up the File Open dialog box to obtain a specified open file.

public:
 int GetOpenFileNameViaDlgEx(cli::array <Microsoft::VisualStudio::Shell::Interop::VSOPENFILENAMEW> ^ pOpenFileName, System::String ^ pszHelpTopic);

int GetOpenFileNameViaDlgEx(std::Array <Microsoft::VisualStudio::Shell::Interop::VSOPENFILENAMEW> const & pOpenFileName, std::wstring const & pszHelpTopic);

public int GetOpenFileNameViaDlgEx (Microsoft.VisualStudio.Shell.Interop.VSOPENFILENAMEW[] pOpenFileName, string pszHelpTopic);

abstract member GetOpenFileNameViaDlgEx : Microsoft.VisualStudio.Shell.Interop.VSOPENFILENAMEW[] * string -> int

Public Function GetOpenFileNameViaDlgEx (pOpenFileName As VSOPENFILENAMEW(), pszHelpTopic As String) As Integer

Parameters

pOpenFileName

VSOPENFILENAMEW[]

[in, out] A VSOPENFILENAMEW structure that contains information used to initialize the File Open dialog box. When this method returns, this structure contains information about the user's file selection.

pszHelpTopic

String

[in] A string containing the help topic.

Returns

Int32

If the method succeeds, it returns S_OK. If it fails, it returns an error code.

Remarks

COM Signature

From vsshell80.idl:

HRESULT IVsUIShell2::GetOpenFileNameViaDlgEx(  
   [in,out] VSOPENFILENAMEW *pOpenFileName,  
   [in]     LPCOLESTR        pszHelpTopic  
);