Integer.HighestOneBit(Int32) Method
Definition
Important
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Returns an int value with at most a single one-bit, in the
position of the highest-order ("leftmost") one-bit in the specified
int value.
[Android.Runtime.Register("highestOneBit", "(I)I", "")]
public static int HighestOneBit (int i);[<Android.Runtime.Register("highestOneBit", "(I)I", "")>]
static member HighestOneBit : int -> intParameters
- i
- Int32
the value whose highest one bit is to be computed
Returns
an int value with a single one-bit, in the position
of the highest-order one-bit in the specified value, or zero if
the specified value is itself equal to zero.
- Attributes
Remarks
Returns an int value with at most a single one-bit, in the position of the highest-order ("leftmost") one-bit in the specified int value. Returns zero if the specified value has no one-bits in its two's complement binary representation, that is, if it is equal to zero.
Added in 1.5.
Java documentation for java.lang.Integer.highestOneBit(int).
Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.