map::value_type

The type of object stored as an element in a map.

typedef pair<const Key, Type> value_type;

Remark

value_type is declared to be pair <const key_type, mapped_type> and not simply pair <key_type, mapped_type> because the keys of an associative container may not be changed using a nonconstant iterator or reference.

Example

// map_value_type.cpp
// compile with: /EHsc
#include <map>
#include <iostream>

int main( )
{
   using namespace std;
   typedef pair <const int, int> cInt2Int;
   map <int, int> m1;
   map <int, int> :: key_type key1;
   map <int, int> :: mapped_type mapped1;
   map <int, int> :: value_type value1;
   map <int, int> :: iterator pIter;
   
   // value_type can be used to pass the correct type
   // explicitly to avoid implicit type conversion
   m1.insert ( map <int, int> :: value_type ( 1, 10 ) );

   // Compare other ways to insert objects into a map
   m1.insert ( cInt2Int ( 2, 20 ) );
   m1[ 3 ] = 30;

   // Initializing key1 and mapped1
   key1 = ( m1.begin( ) -> first );
   mapped1 = ( m1.begin( ) -> second );

   cout << "The key of first element in the map is "
        << key1 << "." << endl;

   cout << "The data value of first element in the map is "
        << mapped1 << "." << endl;

   // The following line would cause an error because
   // the value_type is not assignable
   // value1 = cInt2Int ( 4, 40 );

   cout  << "The keys of the mapped elements are:";
   for ( pIter = m1.begin( ) ; pIter != m1.end( ) ; pIter++ )
      cout << " " << pIter -> first;
   cout << "." << endl;

   cout  << "The values of the mapped elements are:";
   for ( pIter = m1.begin( ) ; pIter != m1.end( ) ; pIter++ )
      cout << " " << pIter -> second;
   cout << "." << endl;
}

Output

The key of first element in the map is 1.
The data value of first element in the map is 10.
The keys of the mapped elements are: 1 2 3.
The values of the mapped elements are: 10 20 30.

Requirements

Header: <map>

Namespace: std

See Also

Reference

map Class

Standard Template Library