SingleLineLambdaExpressionSyntax.WithBegin(LambdaHeaderSyntax) Method
Definition
Important
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Caution
This member is obsolete. Use WithSubOrFunctionHeader instead.
public:
Microsoft::CodeAnalysis::VisualBasic::Syntax::SingleLineLambdaExpressionSyntax ^ WithBegin(Microsoft::CodeAnalysis::VisualBasic::Syntax::LambdaHeaderSyntax ^ begin);
[System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Never)]
[System.Obsolete("This member is obsolete. Use WithSubOrFunctionHeader instead.", true)]
public Microsoft.CodeAnalysis.VisualBasic.Syntax.SingleLineLambdaExpressionSyntax WithBegin (Microsoft.CodeAnalysis.VisualBasic.Syntax.LambdaHeaderSyntax begin);
[<System.ComponentModel.EditorBrowsable(System.ComponentModel.EditorBrowsableState.Never)>]
[<System.Obsolete("This member is obsolete. Use WithSubOrFunctionHeader instead.", true)>]
member this.WithBegin : Microsoft.CodeAnalysis.VisualBasic.Syntax.LambdaHeaderSyntax -> Microsoft.CodeAnalysis.VisualBasic.Syntax.SingleLineLambdaExpressionSyntax
Public Function WithBegin (begin As LambdaHeaderSyntax) As SingleLineLambdaExpressionSyntax
Parameters
- begin
- LambdaHeaderSyntax
Returns
- Attributes
Applies to
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