NameOfExpressionSyntax.WithArgument(ExpressionSyntax) Method
Definition
Important
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Returns a copy of this with the Argument property changed to the specified value. Returns this instance if the specified value is the same as the current value.
public:
Microsoft::CodeAnalysis::VisualBasic::Syntax::NameOfExpressionSyntax ^ WithArgument(Microsoft::CodeAnalysis::VisualBasic::Syntax::ExpressionSyntax ^ argument);public Microsoft.CodeAnalysis.VisualBasic.Syntax.NameOfExpressionSyntax WithArgument (Microsoft.CodeAnalysis.VisualBasic.Syntax.ExpressionSyntax argument);member this.WithArgument : Microsoft.CodeAnalysis.VisualBasic.Syntax.ExpressionSyntax -> Microsoft.CodeAnalysis.VisualBasic.Syntax.NameOfExpressionSyntaxPublic Function WithArgument (argument As ExpressionSyntax) As NameOfExpressionSyntaxParameters
- argument
- ExpressionSyntax
Returns
Applies to
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