basic_string::find_last_of

지정된 된 문자열의 모든 요소와 일치 하는 마지막 문자는 문자열을 통해 검색 합니다.

size_type find_last_of(
    value_type _Ch, 
    size_type _Off = npos
) const;

size_type find_last_of(
    const value_type* _Ptr,
    size_type _Off = npos
) const;

size_type find_last_of(
    const value_type* _Ptr, 
    size_type _Off,
    size_type _Count
) const;

size_type find_last_of(
    const basic_string<CharType, Traits, Allocator>& _Str,
    size_type _Off = npos
) const;

매개 변수

• _Ch
  문자 값 멤버 함수 검색 됩니다.

• _Off
  검색이 완료 되는 위치의 인덱스입니다.

• _Ptr
  -문자열 멤버 함수 검색 됩니다 C.

• _Count
  앞으로 계산 하 여 멤버 함수 검색 되어 C 문자열에서 첫 번째 문자에서 문자의 수입니다.

• _Str
  멤버 함수 검색 되는 문자열입니다.

반환 값

로그인이 성공 하면 부분 문자열의 마지막 문자의 인덱스를 검색. 그렇지 않으면 npos.

예제

// basic_string_find_last_of.cpp
// compile with: /EHsc
#include <string>
#include <iostream>

int main( )
{
   using namespace std;

   // The first member function
   // searches for a single character in a string
   string str1 ( "abcd-1234-abcd-1234" );
   cout << "The original string str1 is: " << str1 << endl;
   basic_string <char>::size_type indexCh1a, indexCh1b;
   static const basic_string <char>::size_type npos = -1;

   indexCh1a = str1.find_last_of ( "d" , 14 );
   if ( indexCh1a != npos )
      cout << "The index of the last 'd' found before the 14th"
           << " position in str1 is: " << indexCh1a << endl;
   else
      cout << "The character 'd' was not found in str1 ." << endl;

   indexCh1b = str1.find_first_of ( "x" );
   if ( indexCh1b != npos )
      cout << "The index of the 'x' found in str1 is: "
           << indexCh1b << endl << endl;
   else
      cout << "The character 'x' was not found in str1."
           << endl << endl;

   // The second member function searches a string
   // for a substring as specified by a C-string
   string str2 ( "ABCD-1234-ABCD-1234" );
   cout << "The original string str2 is: " << str2 << endl;
   basic_string <char>::size_type indexCh2a, indexCh2b;

   const char *cstr2 = "B1";
   indexCh2a = str2.find_last_of  ( cstr2 , 12 );
   if (indexCh2a != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'B1' in str2 before\n the 12th "
           << "position is: " << indexCh2a << endl;
   else
      cout << "Elements of the substring 'B1' were not "
           << "found in str2 before the 12th position."
           << endl;

   const char *cstr2b = "D2";
   indexCh2b = str2.find_last_of  ( cstr2b );
   if ( indexCh2b != npos )
      cout << "The index of the last element of 'D2' "
           << "after\n the 0th position in str2 is: "
           << indexCh2b << endl << endl;
   else
      cout << "The substring 'D2' was not found in str2 ."
           << endl << endl << endl;

   // The third member function searches a string
   // for a substring as specified by a C-string
   string str3 ( "456-EFG-456-EFG" );
   cout << "The original string str3 is: " << str3 << endl;
   basic_string <char>::size_type indexCh3a;

   const char *cstr3a = "5E";
   indexCh3a = str3.find_last_of ( cstr3a , 8 , 8 );
   if ( indexCh3a != npos )
      cout << "The index of the last occurrence of an "
           << "element of '5E' in str3 before\n the 8th "
           << "position is: " << indexCh3a << endl << endl;
   else
      cout << "Elements of the substring '5G' were not "
           << "found in str3\n before the 8th position."
           << endl << endl;

   // The fourth member function searches a string
   // for a substring as specified by a string
   string str4 ( "12-ab-12-ab" );
   cout << "The original string str4 is: " << str4 << endl;
   basic_string <char>::size_type indexCh4a, indexCh4b;

   string str4a ( "ba3" );
   indexCh4a = str4.find_last_of  ( str4a , 8 );
   if ( indexCh4a != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'ba3' in str4 before\n the 8th "
           << "position is: " << indexCh4a << endl;
   else
      cout << "Elements of the substring 'ba3' were not "
           << "found in str4\n after the 0th position."
           << endl;

   string str4b ( "a2" );
   indexCh4b = str4.find_last_of ( str4b  );
   if ( indexCh4b != npos )
      cout << "The index of the last occurrence of an "
           << "element of 'a2' in str4 before\n the 0th "
           << "position is: " << indexCh4b << endl;
   else
      cout << "Elements of the substring 'a2' were not "
           << "found in str4\n after the 0th position."
           << endl;
}

요구 사항

헤더: <string>

네임 스페이스: std

참고 항목

참조

basic_string Class