LanguageService.IsDebugging Property
Determines if the debugger is active.
Namespace: Microsoft.VisualStudio.Package
Assemblies: Microsoft.VisualStudio.Package.LanguageService.9.0 (in Microsoft.VisualStudio.Package.LanguageService.9.0.dll)
Microsoft.VisualStudio.Package.LanguageService.10.0 (in Microsoft.VisualStudio.Package.LanguageService.10.0.dll)
Microsoft.VisualStudio.Package.LanguageService (in Microsoft.VisualStudio.Package.LanguageService.dll)
Syntax
‘선언
Public ReadOnly Property IsDebugging As Boolean
Get
‘사용 방법
Dim instance As LanguageService
Dim value As Boolean
value = instance.IsDebugging
public bool IsDebugging { get; }
public:
property bool IsDebugging {
bool get ();
}
member IsDebugging : bool
function get IsDebugging () : boolean
Property Value
Type: System.Boolean
This property returns true if the debugger is active; otherwise, returns false.
Remarks
A debugger is active if the debug mode does not equal DBGMODE_Design (from the DBGMODE enumeration); this is set when Visual Studio calls the OnModeChange method.
This method is typically called from the ViewFilter class to determine if certain actions can or should be taken.
.NET Framework Security
- Full trust for the immediate caller. This member cannot be used by partially trusted code. For more information, see Using Libraries from Partially Trusted Code.