다음을 통해 공유

  • 아티클

Databases 속성

Database 개체의 컬렉션을 나타냅니다. 각 Database 개체는 SQL Server 인스턴스에 정의된 데이터베이스를 나타냅니다.

네임스페이스:  Microsoft.SqlServer.Management.Smo
어셈블리:  Microsoft.SqlServer.Smo(Microsoft.SqlServer.Smo.dll)

구문

‘선언
<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny,  _
    GetType(Database), SfcObjectFlags.Design)> _
Public ReadOnly Property Databases As DatabaseCollection
    Get
‘사용 방법
Dim instance As Server
Dim value As DatabaseCollection

value = instance.Databases

[SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Database), SfcObjectFlags.Design)]
public DatabaseCollection Databases { get; }

[SfcObjectAttribute(SfcContainerRelationship::ObjectContainer, SfcContainerCardinality::ZeroToAny, 
    typeof(Database), SfcObjectFlags::Design)]
public:
property DatabaseCollection^ Databases {
    DatabaseCollection^ get ();
}

[<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, 
    typeof(Database), SfcObjectFlags.Design)>]
member Databases : DatabaseCollection

function get Databases () : DatabaseCollection

속성 값

유형: Microsoft.SqlServer.Management.Smo. . :: . .DatabaseCollection
SQL Server 인스턴스에 정의된 모든 데이터베이스를 나타내는 DatabaseCollection 개체입니다.

주의

Specific databases can be referenced by using this collection and specifying the name of the database. To create a new database, call the database constructor Database.

예

Visual Basic

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server
'Modify a property using the Databases, Tables, and Columns collections to reference a column.
srv.Databases("AdventureWorks2008R2").Tables("Person", "Person").Columns("ModifiedDate").Nullable = True
'Call the Alter method to make the change on the instance of SQL Server.
srv.Databases("AdventureWorks2008R2").Tables("Person", "Person").Columns("ModifiedDate").Alter()

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = $srv.Databases.Item("AdventureWorks2008R2")
$tb = $db.Tables.Item("Person", "Person")
$col = $tb.Columns.Item("LastName")
$col.Nullable = $TRUE
$col.Alter()