operator!= (unordered_map)

Tests whether the unordered_map object on the left side of the operator is not equal to the unordered_map object on the right side.

bool operator!=( 
   const unordered_map <Key, Type, Hash, Pred, Allocator>& _Left, 
   const unordered_map <Key, Type, Hash, Pred, Allocator>& _Right 
);

매개 변수

• _Left
  unordered_map 형식의 개체입니다.

• _Right
  unordered_map 형식의 개체입니다.

반환 값

true if the unordered_maps are not equal; false if they are equal.

설명

The comparison between unordered_map objects is not affected by the arbitrary order in which they store their elements. Two unordered_maps are equal if they have the same number of elements and the elements in one container are a permutation of the elements in the other container. 그렇지 않으면 두 개체는 서로 다른 개체입니다.

예제

// unordered_map_op_ne.cpp
// compile by using: cl.exe /EHsc /nologo /W4 /MTd 
#include <unordered_map>
#include <iostream>
#include <ios>

int main( )
{
   using namespace std;
   unordered_map<int, int> um1, um2, um3;
   
   for ( int i = 0 ; i < 3 ; ++i ) {
      um1.insert( make_pair( i+1, i ) );
      um1.insert( make_pair( i, i ) );

      um2.insert( make_pair( i, i+1 ) );
      um2.insert( make_pair( i, i ) );
      
      um3.insert( make_pair( i, i ) );
      um3.insert( make_pair( i+1, i ) );
   }

   cout << boolalpha;
   cout << "um1 != um2: " << (um1 != um2) << endl; 
   cout << "um1 != um3: " << (um1 != um3) << endl; 
   cout << "um2 != um3: " << (um2 != um3) << endl; 
}

출력:

um1 != um2: true

um1 != um3: false

um2 != um3: true

요구 사항

헤더:<unordered_map>

네임스페이스: std

참고 항목

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