IUIService.ShowToolWindow(Guid) Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Displays the specified tool window.
public:
bool ShowToolWindow(Guid toolWindow);
public bool ShowToolWindow (Guid toolWindow);
abstract member ShowToolWindow : Guid -> bool
Public Function ShowToolWindow (toolWindow As Guid) As Boolean
Parameters
- toolWindow
- Guid
A Guid identifier for the tool window. This can be a custom Guid or one of the predefined values from StandardToolWindows.
Returns
true
if the tool window was successfully shown; false
if it could not be shown or found.
Examples
The following code example attempts to obtain an instance of the IUIService and invoke the service's ShowToolWindow method.
IUIService^ UIservice = dynamic_cast<IUIService^>(this->GetService( System::Windows::Forms::Design::IUIService::typeid ));
if ( UIservice != nullptr )
UIservice->ShowToolWindow( StandardToolWindows::TaskList );
IUIService UIservice = (IUIService)this.GetService(
typeof( System.Windows.Forms.Design.IUIService ) );
if( UIservice != null )
UIservice.ShowToolWindow(StandardToolWindows.TaskList);
Dim UIservice As IUIService = CType(Me.GetService( _
GetType(System.Windows.Forms.Design.IUIService)), IUIService)
If (UIservice IsNot Nothing) Then
UIservice.ShowToolWindow(StandardToolWindows.TaskList)
End If
Applies to
See also
GitHub에서 Microsoft와 공동 작업
이 콘텐츠의 원본은 GitHub에서 찾을 수 있으며, 여기서 문제와 끌어오기 요청을 만들고 검토할 수도 있습니다. 자세한 내용은 참여자 가이드를 참조하세요.
.NET