CodeGenerationUtilities.GetBaseDomainClassSchemaTypeName Method

Definition

Namespace:

Microsoft.VisualStudio.Modeling.DslDefinition

Assembly:

Microsoft.VisualStudio.Modeling.Sdk.DslDefinition.15.0.dll

Get the schema type name for the base class of the given domain class.

public:
 static System::String ^ GetBaseDomainClassSchemaTypeName(Microsoft::VisualStudio::Modeling::DslDefinition::DomainClass ^ domainClass, System::String ^ currentNamespace, System::Collections::Generic::Dictionary<Microsoft::VisualStudio::Modeling::DslDefinition::DslLibrary ^, System::String ^> ^ xmlNamespaceQualifiers);

public static string GetBaseDomainClassSchemaTypeName (Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass domainClass, string currentNamespace, System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary,string> xmlNamespaceQualifiers);

static member GetBaseDomainClassSchemaTypeName : Microsoft.VisualStudio.Modeling.DslDefinition.DomainClass * string * System.Collections.Generic.Dictionary<Microsoft.VisualStudio.Modeling.DslDefinition.DslLibrary, string> -> string

Public Shared Function GetBaseDomainClassSchemaTypeName (domainClass As DomainClass, currentNamespace As String, xmlNamespaceQualifiers As Dictionary(Of DslLibrary, String)) As String

Parameters

domainClass

DomainClass

DomainClass whose base class schema type name will be returned.

currentNamespace

String

xmlNamespaceQualifiers

Dictionary<DslLibrary,String>

Returns

String

The schema type name of the base class of the given DomainClass or null if a base class could not be determined.