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IfDirectiveTriviaSyntax.WithIfKeyword(SyntaxToken) 메서드

정의

public:
 Microsoft::CodeAnalysis::CSharp::Syntax::IfDirectiveTriviaSyntax ^ WithIfKeyword(Microsoft::CodeAnalysis::SyntaxToken ifKeyword);
public Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntax WithIfKeyword (Microsoft.CodeAnalysis.SyntaxToken ifKeyword);
member this.WithIfKeyword : Microsoft.CodeAnalysis.SyntaxToken -> Microsoft.CodeAnalysis.CSharp.Syntax.IfDirectiveTriviaSyntax
Public Function WithIfKeyword (ifKeyword As SyntaxToken) As IfDirectiveTriviaSyntax

매개 변수

ifKeyword
SyntaxToken

반환

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